We are storing the factorial in parts in array indices. Instead of finding the factorial of given number we are finding the factorials of all numbers upto 100001 in their respective array indices and just print the desired facts.
By taking mod with our self defined value of 10^7 we are in a way compressing the number at each level so that are data types can hold that value.
a[i] = ((i%mod)*(a[i-1]%mod))%mod;
The above line of code is very important to understand the code.
This is the line in which through which we are compressing the number to our data type limits (long long)
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To find the count of numbers in a
given range having odd number of factors.
#Solution Code:
#assignment 23 def count_factors(Number): factor_count=0 for
i in
range(1,int(Number+1)): if Number % i == 0: factor_count += 1 return
factor_count """Function
Ended"""
"""Main program begins here""" a = int(input("Enter the lower
range of number: "))
b = int(input("Enter the Upper range of number(this will be included):
")) print("**************************************************************************")
number_elements = 0 for number
in range(a,b+1): Number_Factor = count_factors(number) if
Number_Factor % 2 == 1: number_elements += 1 print("No. of numbers having odd number of factors are: ",number_elements)
#Ouptut
#Explaination:
Step 1:
Firstly we define a function named a count_factors()
which takes a int variable as its parameter. Here Number is passed
as an formal parameter.
Now we initialize a int variable factor_count
which stores a value 0.
Now we run a for loop and run
it from i = 1 to i = Number. (note: we pass i =Number+1 so that i =
Number is included).
#FOR LOOP BODY
In for loop body we check a condition
whether Number % i == 0 (if i is a factor of Number). If this is true then we
increase the value of factor_count by 1.
At the end of for loop we return
factor_count.
Step 2:
#Drivers Code
We input a lower range value and
store it in variable a and an upper range value and store it in variable
b.
We then initialize a variable number_elements
= 0.
Now we again run a for loop
from number = a to number = b+1 (b+1 so that number = b is
included).
In #For body we pass number
in count_factors() as parameter and store the value returned in a
variable Number_factor.
Now we check if Number_factor
is odd ( if Number_factor % 2 == 1 : )
If true then we increment value of
number_elements by 1 else we continue the loop.
Step 3: End
We print the value of number_elements
obtained after completion of for loop.
